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2022 VCAA Maths Methods Exam 2
Adapted for Year 11. Unit 1 & 2.
This is the full VCE Maths Methods Exam with worked solutions. You can also try Mini-Tests, which are official VCAA exams split into short tests you can do anytime.
Number of marks: 59
Reading time: 10 minutes
Writing time: 90 minutes
Section A – Multiple-choice questions
Instructions
• Answer all questions in pencil on your Multiple-Choice Answer Sheet.
• Choose the response that is correct for the question.
• A correct answer scores 1; an incorrect answer scores 0.
• Marks will not be deducted for incorrect answers.
• No marks will be given if more than one answer is completed for any question.
• Unless otherwise indicated, the diagrams in this book are not drawn to scale.
The period of the function \( f(x) = 3\cos(2x + \pi) \) is
- A. \(2\pi\)
- B. \( \pi \)
- C. \( \frac{2\pi}{3} \)
- D. 2
- E. 3
The graph of \( y = \frac{1}{(x + 3)^2} + 4 \) has a horizontal asymptote with the equation
- A. \( y = 4 \)
- B. \( y = 3 \)
- C. \( y = 0 \)
- D. \( x = -2 \)
- E. \( x = -3 \)
The largest value of \( a \) such that the function \( f : (-\infty, a] \to \mathbb{R}, f(x) = x^2 + 3x - 10 \), where \( f \) is one-to-one, is
- A. –12.25
- B. –5
- C. –1.5
- D. 0
- E. 2
Which of the pairs of functions below are not inverse functions?
- A. \( \begin{cases} f(x) = 5x + 3 \quad x \in \mathbb{R} \\ g(x) = \frac{x - 3}{5} \quad x \in \mathbb{R} \end{cases} \)
- B. \( \begin{cases} f(x) = \frac{2}{3}x + 2 \quad x \in \mathbb{R} \\ g(x) = \frac{3}{2}x - 3 \quad x \in \mathbb{R} \end{cases} \)
- C. \( \begin{cases} f(x) = x^2 \quad x < 0 \\ g(x) = \sqrt{x} \quad x > 0 \end{cases} \)
- D. \( \begin{cases} f(x) = \frac{1}{x} \quad x \ne 0 \\ g(x) = \frac{1}{x} \quad x \ne 0 \end{cases} \)
- E. \( \begin{cases} f(x) = \log_e(x) + 1 \quad x > 0 \\ g(x) = e^{x - 1} \quad x \in \mathbb{R} \end{cases} \)
The graph of \( y = f(x) \) is shown below.
The graph of \( y = f'(x) \), the first derivative of \( f(x) \) with respect to \( x \), could be
If \( \int_0^b f(x)\,dx = 10 \) and \( \int_0^a f(x)\,dx = -4 \), where \( 0 < a < b \), then \( \int_a^b f(x)\,dx \) is equal to
- A. –6
- B. –4
- C. 0
- D. 10
- E. 14
Let \( f : [0, \infty) \to \mathbb{R}, \ f(x) = \sqrt{2x + 1} \).
The shortest distance, \( d \), from the origin to the point \( (x, y) \) on the graph of \( f \) is given by
- A. \( d = x^2 + 2x + 1 \)
- B. \( d = x^2 + \sqrt{2x + 1} \)
- C. \( d = \sqrt{x^2 - 2x + 1} \)
- D. \( d = x + 1 \)
- E. \( d = 2x + 1 \)
The function \( f(x) = \log_3\left(\frac{a + x}{a - x}\right) \), where \( a \) is a positive real constant, has the maximal domain
- A. [–a, a]
- B. (–a, a)
- C. \( \mathbb{R} \setminus [–a, a] \)
- D. \( \mathbb{R} \setminus (–a, a) \)
- E. \( \mathbb{R} \)
The maximal domain of the function with rule \( f(x) = \sqrt{x^2 - 2x - 3} \) is given by
- A. \( (-\infty, \infty) \)
- B. \( (-\infty, -3) \cup (3, \infty) \)
- C. \( (-1, 3) \)
- D. [–3, 1]
- E. \( (-\infty, -1] \cup [3, \infty) \)
The function \( f(x) = \frac{1}{3}x^3 + mx^2 + nx + p \), for \( m, n, p \in \mathbb{R} \), has turning points at \( x = -3 \) and \( x = 1 \) and passes through the point (3, 4).
The values of \( m, n \) and \( p \) respectively are
- A. \( m = 0, n = -\frac{7}{3}, p = 2 \)
- B. \( m = 1, n = -3, p = -5 \)
- C. \( m = -1, n = -3, p = 13 \)
- D. \( m = \frac{5}{4}, n = \frac{3}{2}, p = -\frac{83}{4} \)
- E. \( m = \frac{5}{2}, n = 6, p = -\frac{91}{2} \)
A function \( g \) is continuous on the domain \( x \in [a, b] \) and has the following properties:
• The average rate of change of \( g \) between \( x = a \) and \( x = b \) is positive.
• The instantaneous rate of change of \( g \) at \( x = \frac{a + b}{2} \) is negative.
Therefore, on the interval \( x \in [a, b] \), the function must be
- A. many-to-one
- B. one-to-many
- C. one-to-one
- D. strictly decreasing
- E. strictly increasing
If \( X \) is a binomial random variable where \( n = 20, p = 0.88 \), and \( \Pr(X \geq 16 \mid X \geq a) = 0.9175 \), correct to four decimal places, then \( a \) is equal to
- A. 11
- B. 12
- C. 13
- D. 14
- E. 15
A box is formed from a rectangular sheet of cardboard, which has a width of \( a \) units and a length of \( b \) units, by first cutting out squares of side length \( x \) units from each corner and then folding up to form an open-top container.
The maximum volume of the box occurs when \( x \) is equal to
- A. \( \frac{a - b + \sqrt{a^2 - ab + b^2}}{6} \)
- B. \( \frac{a + b + \sqrt{a^2 - ab + b^2}}{6} \)
- C. \( \frac{a - b - \sqrt{a^2 - ab + b^2}}{6} \)
- D. \( \frac{a + b - \sqrt{a^2 - ab + b^2}}{6} \)
- E. \( \frac{a + b - \sqrt{a^2 - 2ab + b^2}}{6} \)
End of Section A
Section B
Instructions
• Answer all questions in the spaces provided.
• Write your responses in English.
• In questions where a numerical answer is required, an exact value must be given unless otherwise specified.
• In questions where more than one mark is available, appropriate working must be shown.
• Unless otherwise indicated, the diagrams in this book are not drawn to scale.
The diagram below shows part of the graph of \( y = f(x) \), where \( f(x) = \frac{x^2}{12} \).
a. State the equation of the axis of symmetry of the graph of \( f \). 1 mark
b. State the derivative of \( f \) with respect to \( x \). 1 mark
The tangent to \( f \) at point M has gradient −2.
c. Find the equation of the tangent to \( f \) at point M. 2 marks
The diagram below shows part of the graph of \( y = f(x) \), the tangent to \( f \) at point M and the line perpendicular to the tangent at point M.
d. i. Find the equation of the line perpendicular to the tangent passing through point M. 1 mark
ii. The line perpendicular to the tangent at point M also cuts \( f \) at point N, as shown in the diagram above.
Find the area enclosed by this line and the curve \( y = f(x) \). 2 marks
e. Another parabola is defined by the rule \( g(x) = \frac{x^2}{4a} \), where \( a > 0 \).
A tangent to \( g \) and the line perpendicular to the tangent at \( x = -b \), where \( b > 0 \), are shown below.
Find the value of \( b \), in terms of \( a \), such that the shaded area is a minimum. 4 marks
On a remote island, there are only two species of animals: foxes and rabbits. The foxes are the predators and the rabbits are their prey.
The populations of foxes and rabbits increase and decrease in a periodic pattern, with the period of both populations being the same, as shown in the graph below, for all \( t \geq 0 \), where time \( t \) is measured in weeks.
One point of minimum fox population, \( (20, 700) \), and one point of maximum fox population, \( (100, 2500) \), are also shown on the graph.
The graph has been drawn to scale.
a. i. State the initial population of rabbits. 1 mark
ii. State the minimum and maximum population of rabbits. 1 mark
iii. State the number of weeks between maximum populations of rabbits. 1 mark
The population of foxes can be modelled by the rule \( f(t) = a \sin\big(b(t - 60)\big) + 1600 \).
b. Show that \( a = 900 \) and \( b = \frac{\pi}{80} \). 2 marks
c. Find the maximum combined population of foxes and rabbits. Give your answer correct to the nearest whole number. 1 mark
d. What is the number of weeks between the periods when the combined population of foxes and rabbits is a maximum? 1 mark
[The following question is no longer on the curriculum]
The population of foxes is better modelled by the transformation of \( y = \sin(t) \) under \( Q : \mathbb{R}^2 \rightarrow \mathbb{R}^2, \, Q \begin{pmatrix} t \\ y \end{pmatrix} = \begin{pmatrix} \frac{90}{\pi} & 0 \\ 0 & 900 \end{pmatrix} \begin{pmatrix} t \\ y \end{pmatrix} + \begin{pmatrix} 60 \\ 1600 \end{pmatrix} \).
e. Find the average population during the first 300 weeks for the combined population of foxes and rabbits, where the population of foxes is modelled by the transformation of \( y = \sin(t) \) under the transformation \( Q \). Give your answer correct to the nearest whole number. 4 marks
Over a longer period of time, it is found that the increase and decrease in the population of rabbits gets smaller and smaller.
The population of rabbits over a longer period of time can be modelled by the rule
\( s(t) = 1700 \cdot e^{-0.003t} \cdot \sin\left( \frac{\pi t}{80} \right) + 2500, \quad \text{for all } t \geq 0 \)
f. Find the average rate of change between the first two times when the population of rabbits is at a maximum. Give your answer correct to one decimal place. 2 marks
g. Find the time, where \( t > 40 \), in weeks, when the rate of change of the rabbit population is at its greatest positive value. Give your answer correct to the nearest whole number. 2 marks
h. Over time, the rabbit population approaches a particular value.
State this value. 1 mark
Mika is flipping a coin. The unbiased coin has a probability of \( \frac{1}{2} \) of landing on heads and \( \frac{1}{2} \) of landing on tails.
Let \( X \) be the binomial random variable representing the number of times that the coin lands on heads. Mika flips the coin five times.
a. i. Find \( \Pr(X = 5) \). 1 mark
ii. Find \( \Pr(X \geq 2) \). 1 mark
iii. Find \( \Pr(X \geq 2 \mid X < 5) \), correct to three decimal places. 2 marks
iv. Not applicable for Year 11 students. 2 marks
b. Not applicable for Year 11 students
Consider the function \( f : \left( -\frac{1}{2}, \frac{1}{2} \right) \rightarrow \mathbb{R} \), \( f(x) = \log_e\left(x + \frac{1}{2}\right) - \log_e\left(\frac{1}{2} - x\right) \).
Part of the graph of \( y = f(x) \) is shown below.
a. State the range of \( f(x) \). 1 mark
b. i. Find \( f'(0) \). 2 marks
ii. State the maximal domain over which \( f \) is strictly increasing. 1 mark
c. Show that \( f(x) + f(-x) = 0 \). 1 mark
d. Find the domain and the rule of \( f^{-1} \), the inverse of \( f \). 3 marks
e. Not applicable for Year 11 students
Let \( g(x) = f(\sin(2x)) \), where the function \( f \) is differentiable.
The following table gives values for \( f(x) \) and \( f'(x) \):
| \( x \) | \( \frac{1}{2} \) | \( \frac{\sqrt{2}}{2} \) | \( \frac{\sqrt{3}}{2} \) |
|---|---|---|---|
| \( f(x) \) | \( -2 \) | \( 5 \) | \( 3 \) |
| \( f'(x) \) | \( 7 \) | \( 0 \) | \( \frac{1}{9} \) |
a. Find the value of \( g\left( \frac{\pi}{6} \right) \). 1 mark
The derivative of \( g \) with respect to \( x \) is given by \( g'(x) = 2 \cdot \cos(2x) \cdot f'(\sin(2x)) \).
b. Show that \( g'\left( \frac{\pi}{6} \right) = \frac{1}{9} \). 1 mark
c. Find the equation of the tangent to \( g \) at \( x = \frac{\pi}{6} \). 2 marks
d. Not applicable for Year 11 students. 2 marks
e. Find four solutions to the equation \( g'(x) = 0 \) for the interval \( x \in [0, \pi] \). 3 marks
End of examination questions
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