VCE Maths Methods Integral Calculus Mini Test 9

Number of marks: 10

Reading time: 2 minutes

Writing time: 15 minutes

Section A Calculator Allowed
Instructions
• Answer all questions in pencil on your Multiple-Choice Answer Sheet.
• Choose the response that is correct for the question.
• A correct answer scores 1; an incorrect answer scores 0.
• Marks will not be deducted for incorrect answers.
• No marks will be given if more than one answer is completed for any question.
• Unless otherwise indicated, the diagrams in this book are not drawn to scale.


Question 1 [2018 Exam 2 Section A Q8]

If \(\int_1^{12} g(x)dx = 5\) and \(\int_{12}^{5} g(x)dx = -6\), then \(\int_1^{5} g(x)dx\) is equal to

  • A. \(-11\)
  • B. \(-1\)
  • C. \(1\)
  • D. \(3\)
  • E. \(11\)
Correct Answer: B
Click here for full solution
Question 2 [2017 Exam 2 Section A Q20]

The graphs of \(f: [0, \frac{\pi}{2}] \to R, f(x) = \cos(x)\) and \(g: [0, \frac{\pi}{2}] \to R, g(x) = \sqrt{3}\sin(x)\) are shown below.
The graphs intersect at \(B\).

Graphs of cos(x) and sqrt(3)sin(x) from 0 to pi/2, showing the shaded area under the upper envelope.

The ratio of the area of the shaded region to the area of triangle \(OAB\) is

  • A. \(9:8\)
  • B. \(\sqrt{3}-1 : \frac{\sqrt{3}\pi}{8}\)
  • C. \(8\sqrt{3}-3 : 3\pi\)
  • D. \(\sqrt{3}-1 : \frac{\sqrt{3}\pi}{4}\)
  • E. \(1 : \frac{\sqrt{3}\pi}{8}\)
Correct Answer: B
Click here for full solution

End of Section A


Section B – No Calculator
Instructions
• Answer all questions in the spaces provided.
• Write your responses in English.
• In questions where a numerical answer is required, an exact value must be given unless otherwise specified.
• In questions where more than one mark is available, appropriate working must be shown.
• Unless otherwise indicated, the diagrams in this book are not drawn to scale.


Question 1 [2018 Exam 1 Q2]

The derivative with respect to \(x\) of the function \( f: (1, \infty) \rightarrow \mathbb{R} \) has the rule \( f'(x) = \frac{1}{2} - \frac{1}{(2x-2)} \).
Given that \( f(2) = 0 \), find \( f(x) \) in terms of \(x\). 3 marks

Question 2 [2019 Exam 1 Q5]

Let \(f: \mathbb{R}\setminus\{1\} \to \mathbb{R}\), \(f(x) = \frac{2}{(x-1)^2} + 1\).

a.

i. Evaluate \(f(-1)\). 1 mark

ii. Sketch the graph of \(f\) on the axes below, labelling all asymptotes with their equations. 2 marks

Axes for sketching the graph of f(x).

b. Find the area bounded by the graph of \(f\), the \(x\)-axis, the line \(x=-1\) and the line \(x=0\). 2 marks


End of examination questions

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